I can explain why it is lw but I have trouble explaining why it is (l-n)(w-n) n=a value I know that this formula is used to work out the number of the different sized squares in the grid.
Is it because each size square within the grid takes up a certain number of 1x1 squares and that is why you can fit less 1x1 squares in so you have to -n? Thankyou Sheena Lam Hello, I am wondering if anybody here is doing maths coursework that involves finding the number of squares in a grid.
Number Stairs Maths Coursework - nhatmypham ...https:// The coursework element was removed from GCSE Mathematics assessments in September 2007. The numbers 1 and 16 are one pair of opposites in this 4 by 4 grid.
The numbers 4 and 13 are the other pair of opposites ...https://answers.yahoo.com/question/index?
Using the following example I will explain what limitations apply to the width of the grid.
Putting the square in column 6 will mean that there will still be a column with nothing in it in front of the rectangle on the grid. This gives me the last column that the rectangle will work in.
I also like how an explanation can be shown for each step. I have one more math class to take and I am sure I will put the Algebrator to good use then!
That helps learn the functions of each different method for solving. Reese Pontoon, MO I want to thank you for all you help.
I cannot find one general rule that connects the number of squares with the size of the grid though I can see a pattern in finding the rules linking the number of squares to the size of the grid if only the length or width remains constant: l=length w=width For example, this is the rule to find out the number of squares present in a 5x3 grid: lw (l-1)(w-1) (l-2)(w-2) I have found out rules such as the above for different sized grids and have compared them to see if they have anything in common.
I have found that they do have something in common and that is that they all begin with lw and end on (l-(w-1))(w-(w-1)).